A ball of `5kg` experiences a force `F=2x^(2)+x` .Work-done in displacing the ball from `x=0` to `x=2m`is :- ?

The force acting on a bod moving parallel to the X-axis is F=3x+2x^(2) . What is the work done in displacing the body from x=1 to x=2 ?

The work done by a force vec(F)=(-6x^(3)hat(i)) N in displacing a particle from x = 4m to x = - 2m is

The relationship between the force F and position x of body is as shown in figure. The work done in displacing the body from ( x = 1 m to x = 5 m ) will be .

A force F acting on a particle varies with the position x as shown in the graph. Find the work done by the force in displacing the particle from x =-a to x = +2a . .

A force F=Kx^(2) acts on a particle at an angle of 60° with the x–axis. the work done in displacing the particle from x_(1) to x_(2) will be –

Adjacent figure shows the force-displacement graph of a moving body, the work done in displacing body from x=0 to x=35m is equal to

A position dependent force F=7-2x+3x^(2) acts on a small body of mass 2 kg and displaced it from x=0 to x=5m . Calculate the work done in joule.