The potential energy of a harmonic oscillation when is half way to its and end point is (where `E` it’s the total energy)

If the potential energy of a harmonic oscillator of mass 2kg on its equilbrium position is 5 joules and the total energy is 9 joules when the amplitude is one meter the period of the oscillator ("in" sec) is-

The potential energy of a harmonic oscillator of mass 2 kg in its mean positioin is 5J. If its total energy is 9J and its amplitude is 0.01m, its period will be

The potential energy of a simple harmonic oscillator of mass 2 kg in its mean position is 5 J. If its total energy is 9 J and its amplitude is 0.01 m, its time period would be

The potential energy of a harmonic oscillator of mass 2kg in its equilibrium position is 5 joules. Its total energy is 9 joules and its amplitude is 1cm. Its time period will be

When the displacement of a simple harmonic oscillator is half of its amplitude, its potential energy is 3J. Its total energy is

If the total energy of a simple harmonic oscillator is E, then its potential energy, when it is halfway to its endpoint will be

The potential energy of a particle executing S H M is 25 J. when its displacement is half of amplitude. The total energy of the particle is

At which position the potential energy of a harmonic oscillator is maximum or minimum ?

The energy of a simple harmonic oscillator in the state of rest is 3 Joules. If its mean K.E. is 4 joules, its total energy will be :

The potential energy of a particle execuring S.H.M. is 2.5 J, when its displacement is half of amplitude. The total energy of the particle be