The probability of a man hitting a target in one fire is `1/5.` Then the minimum number of fire he must follow in order-or-to make his chance of hitting the target more than `3/4` is

The probability of a man hitting a target in one fire is 1/4 . How many times at least must he fire at the target in order that his chance of hitting the target at least once will exceed 2/3 ?

The probability of a man hitting a target 2 is He fires at the target K times (k a 5 given number). Then the minimum k so that the probability of hitting the target 7 at least once is more than 10 is

The probability of a shooter hitting a target is (3)/(4). How many minimum number of xx must he/she fire so that the probability of hitting the target at least once is more than 0.99?

If the probability of hitting a target by a shooter, in any shot is 1/3, then the minimum number of independent shots at the target required by him so that the probability of hitting the target at least once is greater than (5)/(6) is

A man can hit a target 2 times out of every 3 shots. The least number of times he must shoot, so that the probability of hitting the target at least twice is more than 0.9 is

The probability of a man hitting a target is 0.25. He shoots 7 xx.What is the probability of his hitting at least twice?

The probability of a man hitting a target is 1/2. How many xx must he fire so that the probability of hitting the target at least once is more than 90% .

The probability of a man hitting a target is 1/4. How many xx must he fire so that the probability of his hitting the target at lest once is greater than 2/3?

The probability that a shooter hits a target is (1)/(3). The minimum number of trials such that probability hitting the target atleast once is greater than (5)/(6) is equal to (a) 4 (b) 5 (c) 6 (d)