A man of mass m=60kg is standing on weighing machine fixed on a triangular wedge of angle `theta`=`60^(@)` as shown in the figure. The wedge is moving up with an upward acceleration `alpha=2m//s^(2)`. The weight regiatered by machine is

A block of mass m resting on a wedge of angle theta as shown in the figure. The wedge is given an acceleration a. What is the minimum value of a so that the mass m falls freely ?

A man of mass 60kg is standing on a weighing machine kept in a box of mass 30kg as shown in the diagram If the man man ages to keep the box stationary, find the read ing of the weighing machine .

A block of mass m is placed on weighing machine and it is also attached with a spring balance. The whole system is placed in a lift as shown in figure. Left is moving with constant acceleration 10 m//s^(2) in upward direction. The reading of the weighing machine is 500 N and the reading of spring balance is 300 N. Find the actual mass of the block in kg. (Takr g = 10 m//s^(2) )

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 2m//s^(2) , v = 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a= 2 m//s^(2), v = - 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 2m//s^(2) ,v = 0

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a = 0 , v = 2 m//s

A man of mass 60kg is standing on a weighing machine placed in a lift moving with velocity 'v' and acceleration 'a' as shown in figure. Calculate the reading of weighing machine in following situation : ( g = 10 m//s^(2) ) a=0, v = 0

A man is standing on a weighing machine placed in a lift. When stationary his weight is recorded as 40 kg . If the lift is accelerated upwards with an acceleration of 2m//s^(2) , then the weight recorded in the machine will be (g=10m//s^(2))