From a circular disc of radius R, a square is cut out with a radius as its diagonal. The center of mass of remaining portion is at a distance from the center)

From the circular disc of radius 4R two small discs of radius R are cut off. The centre of mass of the new structure will be at

A circular disc of radius R is removed from a bigger circular disc of radius 2 R such that the circumferences of the discs coincide. The center of mass of new disc is alpha R from the center of the bigger disc. The value of alpha is

From a circular disc of mass M and radius R , a part of 60^(@) is removed. The M.I. of the remaining portion of disc about an axis passing through the center and perpendicular to plane of disc is

From a circular disc of radius R , a triangular portion is cut (sec figure). The distance of the centre of mass of the remainder from the centre of the disc is -

A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the cirucmferences of the discs coincide. The centre of mass of the new disc is alpha/R from the center of the bigger disc. The value of alpha is

From a uniform circular disc of mass M and radius R a small circular disc of radius R/2 is removed in such a way that both have a common tangent. Find the distance of centre of mass of remaining part from the centre of original disc.

A circular disc of radius R is removed from a bigger circular disc of radius 2R such that the circumference of the discs coincoid . The centre of mass of the new disc is alphaR from the centre of the bigger disc . the value of alpha is

A uniform circular plate of radius 2R has a circular hole of radius R cut out of it. The centre of the smaller circle is at a distance of R/3 from the centre of the larger circle. What is the position of the centre of mass of the plate?

Find the position of centre of mass of a uniform disc of radius R from which a hole of radius is cut out. The centre of the hole is at a distance R/2 from the centre of the disc.