Pure benzene freezes at `5.45^(@)C` at a certain place but a 0.374m solution of tetrachloroethane in benzene freezes at `3.55^(@)C`. The `K_(f)` for benzene is

Pure benzene freeze at 5.45^(@)"C" . A solution containing 7.24g of "C"_(2)"H"_(2)"Cl_(4) in 115.3 g of benzene was observed to freeze at 3.55^(@)"C". What is the molal freezing point constant of benzene?

Pure benzene freezes t 5.3^(@)C . A solution of 0.223 g of phenylacetic acid (C_(6)H_(5)CH_(2)COOH) in 4.4 g of benzene (K_(f) = 5.12 Kkg mol^(-1)) freezes at 4.47^(@)C . From the observation one can conclude that :

The freezing point of a solution contaning 0.3 g of acetic acid in 43 g of benzene reduces by 0.3^(@) . Calculate the Van's Hoff factor "( K_(f) for benzene = 5.12 K kg mol^(-1) )"