From a complete ring of mass "m" and radius 'R' a 30∘ sector is removed.The M.I.of the remaining ring about an axis through centre of ring and normal to its plane is

From a complete ring of mass M and radius R , a 30^@ sector is removed. The moment of inertia of the incomplete ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is ,

From a ring of mass M and radius R, a 30^o sector is removed. The moment of inertia of the remaining portion of the ring, about an axis passing through the centre and perpendicular to the plane of the ring is

For a uniform ring of mass M and radius R at its centre

The M.I. of a thin ring of mass M and radius R about an axis through the diameter in its plane will be:

From a circular ring of mass M and radius R, an arc corresponding to a 90^(@) sector is removed. The moment of inertia of the ramaining part of the ring about an axis passing through the centre of the ring and perpendicular to the plane of the ring is k times MR^(2). Then the value of k is

From a disc of radius r_(1) , a concentric disc of radius r_(2) is removed . The mass of the remaining portion is m . Find the M.I. of the remaining about an axis passing through the center of mass and perpendicular to the plane.

Calculate the moment of inertia of a ring having mass M , radius R and having uniform mass distribution about an axis passing through the centre of the ring and perpendicular to the plane of the ring?

The M.I. of a ring of mass M and radius R about a tangential axis perpendicular to its plane is :

A disc of radius r is removed from the centre of a disc of mass M and radius R. The M.I. About the axis through the centre and normal to the plane will be: