If `x=a sin(omegat+(pi)/6)` and `x= a cos omegat`, then what is the phase difference between the two waves?

Two equations of two SHM y = a sin (omegat-alpha) and y = a cos (omegat-alpha) . The phase difference between the two is

Two SHM's are represented by y = a sin (omegat - kx) and y = b cos (omegat - kx) . The phase difference between the two is :

Two equations of two S.H.M. are y=alpha sin (omegat-alpha) and y=b cos ( omega t -alpha) . The phase difference between the two is

Two waves are given by y_(1)=asin(omegat-kx) and y_(2)=a cos(omegat-kx) . The phase difference between the two waves is -

Two SHMs are respectively represented by y_(1)=a sin (omegat-kx) and y_(2)=b cos(omegat-kx) . The phase difference between the two is

Two waves are represented by Y_1=a_1 cos (omegat-kx) and Y-2 =a_2 sin (omegat-kx+pi//3) Then the phase difference between them is-

The equation of the displacement of two particles making SHM are represented by y_(1) = a sin (omegat +phi) & y_(2) - a cos (omegat) . Phase difference between velocities of two particles is

Two particle are executing simple harmonic motion. At an instant of time t their displacement are y_(1)=a "cos"(omegat) and y_(2)=a "sin" (omegat) Then the phase difference between y_(1) and y_(2) is