A sonometer wire of length `L` is plucked at a distance `L//8` from one end then it vibrates with a minimum frequency `n`. If the same wire plucked at a distance `L//6` from another end the minimum frequency with which it vibrates is

A string of length L is fixed at both ends . It is vibrating in its 3rd overtone with maximum amplitude a. The amplitude at a distance L//3 from one end is

A sonometer wire of density rho and radius r is held between two bridges at a distance L apart . Tension in the wire is T. then the fundamental frequency of the wire will be

A string of length l is fixed at both ends and is vibrating in second harmonic. The amplitude at anti-node is 2 mm. The amplitude of a particle at distance l//8 from the fixed end is

A string of length 'l' is fixed at both ends. It is vibrating in its 3^(rd) overtone with maximum ampltiude 'a' . The amplitude at a distance (l)/(3) from one end is = sqrt(p)(a)/(2) . Find p .

When a body of mass 25Kg is suspended from a sonometer wire then it vibrates with frequency 200 Hz. If the volume of the body is 0.009 m3 and it is immersed in water then the frequency of vibration of the wire will be -

A sonometer wire of length L_(1) and vibrating in its fundamental mode is in unison with a tuning fork of frequency n. When the vibrating length of the same wire is reduced to L_(2) , it produces x beats/second with the fork. What is the frequency of teh fork ?

A sonometer wire of length 65cm is in resonance with a tuning fork of frequency N. If the length of the wire is decreased by 1cm and it is vibrated with the same tuning fork, 8 beats/s are heard, then the frequency of the tuning fork will be