A vehicle of mass `m` is moving on a rough horizontal road with momentum `P` . If the coefficient of friction between the tyres and the road be `mu`, then the stopping distance is:

A vehicle of mass m is moving on a rough horizontal road with momentum P . If the coefficient of friction between the tyres and the road br mu, then the stopping distance is:

A vehicle of mass M is moving on a rough horizontal road with a momentum P If the coefficient of friction between the tyres and the road is mu is then the stopping distance is .

A car is moving along a straight horizontal road with a speed v_(0) . If the coefficient of friction between the tyre and the road is mu, the shortest distance in which the car can be stopped is.

A car is moving along a straight horizontal road with a speed v_(0) . If the coefficient of friction between the tyres and the road is mu , the shortest distance in which the car can be stopped is

Consider a car moving along a straight horizontal road with a speed of 72 km / h . If the coefficient of kinetic friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is [g=10ms^(-2)]

Consider a car moving along a straight horizontal road with a speed of 72 km/h. If the coefficient of static friction between the tyres and the road is 0.5, the shortest distance in which the car can be stopped is [g=10 ms^(-1)]

What is done to increase friction between the tyres and road ?

An automobile is moving on a horizontal road with a speed upsilon If the coefficient of friction between the tyres and the road is mu show that the shortest distance in which the automobile can be stooped is upsilon^(2)//2 mu g .

A car is travelling along a curved road of radius r. If the coefficient of friction between the tyres and the road is mu the car will skid if its speed exceeds .