There is a current of 1.344 amp in a copper wire whose area of cross-section normal to the length of the wire is `1 mm^(2)`. If the number of free electrons per `cm^(2)` is `8.4 xx 10^(22)` then the drift velocity would be

Threre is a current of 1.344 a in a copper wire whose area of cross-sectional normal to the length of wire is 1mm^(2) . If the number of free electrons per cm^(2) is 8.4xx10^(28)m^(3) , then the drift velocity would be

There is a current of 40 ampere in a wire of 10^(-6)m^(2) are of cross-section. If the number of free electron per m^(3) is 10^(29) then the drift velocity will be

There is a current of 0.21 A in a copper wire of area of cross section 10^(-6)m^(2) . If the number of electrons per m^(3) is 18.4xx10^(28) then the drift velocity is ( e=1.6xx10^(-19)C )

There is a current of 40 A in a wire 10^(-6)m^(2) area of cross-section. If the number of free electrons per cubic metre is 10^(29) , then the drift velocity is :

There is a current of 20 amperes in a copper wire of 10^(-6) square metre area of cross-section. If the number of free electrons per cubic metre is 10^(29) then the drift velocity is

There is a current of "4.0A" in a wire of cross-sectional area 10^(-6)m^(2) .If the free electron density in wire is 10^(28)m^(-3) ,the drift velocity is :

A copper wire has a square cross-section, 2.0 mm on a side. It carries a current of 8 A and the density of free electrons is 8 xx 10^(28)m^(-3) . The drift speed of electrons is equal to

A current of 1.8 A flows through a wire of cross-sectional area 0.5 mm^(2) ? Find the current density in the wire. If the number density of conduction electrons in the wire is 8.8 xx 10^(28) m^(-3) , find the drift speed of electrons.

Calculate the drift speed of the electrons when 1A of current exists in a copper wire of cross section 2 mm^(2) .The number of free electrons in 1cm^(3) of copper is 8.5xx10^(22) .