A small body of mass m falls to the earth from infintie distance away. What will be its velocity or reaching the earth? (Radius of the earth = R, acceleration due to gravity on the surface of the earth is g) :-

Mass remaining the same, if radius of the earth is doubled, acceleration due to gravity on the surface of the earth would be (g is present value)

If R is the radius of the earth and g the acceleration due to gravity on the earth’s surface, the mean density of the earth is

If R is the radius of the earth and g the acceleration due to gravity on the earth's surface, the mean density of the earth is

A body which is initially at rest at a height R above the surface of the earth of radius R, falls freely towards the earth. Find out its velocity on reaching the surface of earth. Take g= acceleration due to gravity on the surface of the Earth.

A body is projected vertically upward from the surface of the earth with escape velocity. Calculate the time in which it will be at a height (measured from the surface of the arth) 8 time the radius of the earth (R). Acceleration due to gravity on the surface of the earth is g.

A particle of mass 'm' is raised to a height h = R from the surface of earth. Find increase in potential energy. R = radius of earth. g = acceleration due to gravity on the surface of earth.

What will be the acceleration due to gravity at height h if h gt gt R . Where R is radius of earth and g is acceleration due to gravity on the surface of earth

What will be the acceleration due to gravity at height h lt lt R . Where R is radius of earth and g is acceleration to gravity on the surface earth

If V, R and g denote respectively the escape velocity from the surface of the earth radius of the earth, and acceleration due to gravity, then the correct equation is