When `KMnO_(4)` is heated with fused KOH, then the product formed is

Options

A. `KMnO_(4)`, purple
B. `K_(2)MnO_(4)`, green
C. `MnO_(2)`, black
D. `Mn_(2)O_(3)`, brown

Answer

To determine the product formed when potassium permanganate (KMnO₄) is heated with fused potassium hydroxide (KOH), we can follow these steps:

### Step 1: Understand the Reactants
- **KMnO₄** is potassium permanganate, which is a strong oxidizing agent and is typically purple in color.
- **KOH** is potassium hydroxide, which is a strong base.

### Step 2: Identify the Reaction Conditions
- The reaction occurs when KMnO₄ is heated with fused KOH. Fused KOH means that KOH is in a molten state, which can facilitate reactions between the components.

### Step 3: Write the Reaction
- When KMnO₄ is heated with fused KOH, it undergoes a redox reaction. The manganese in KMnO₄ is reduced from an oxidation state of +7 to +6.
- The balanced chemical equation for the reaction is:
\[ 2 KMnO₄ + 2 KOH \rightarrow 2 K₂MnO₄ + H₂O + O₂ \]
- The product formed is **K₂MnO₄**, which is potassium manganate.

### Step 4: Identify the Color of the Product
- K₂MnO₄ is typically green in color, which is a key characteristic that helps in identifying the product.

### Step 5: Conclusion
- The product formed when KMnO₄ is heated with fused KOH is **K₂MnO₄**, which is green in color.

### Final Answer
The product formed is **K₂MnO₄** (potassium manganate), which is green in color.

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