Given that `barx=(sumf_ix_i)/(sumf_i)` . Calculate `barx` if `sumf_ix_i=760` and `sumf_i =50`

Given that barx=(sumf_ix_i)/(sumf_i) .Find sumf_i if barx =14 and sumf_ix_i=420

Mean barx=A+(sumf_id_i)/(sumf_i) .Find barx if A=29.5 sumf_id_i= -15 and sumf_i=25 .

A.M. barx=A+(sumf_id_i)/(sumf_i) in this formulae A= ________

The mean for a grouped data is calculated by overlinex=a+(sumf_id_i)/(sumf_i) . What do the terms 'f_i' and 'd_i' represent in the above formula?

barx=A+(sumf_i d_i)/(sumf_i) is the formula to find mean for an ungrouped data. In this formula letter A represents for

The sum and sum of squares corresponding to length x (in cm) and weighty (k. gm) of 50 plant products are given below: sum_(i=1)^(50) x_(i) = 212 , sum_(i=1)^(50) x_(i)^(2)=902.8 , sum_(i=1)^(50) y^(i)=261 , sum_(i=1)^(50) y_(i)^(2)=1457.6 Which is more varying , the length or weight ?

In a deviation problem sumf_id_i=-12 and A=15, sumf=20 , then barx =

If I calculate the probability of an events as -0.5, then