` dy/dx + 2xy - x = 0, y(0) = 3.`

(1 + x^(2)) (dy)/(dx) + 2xy = 4x ^(2) , given that y = 0 , when x =0

if ( dy )/(dx) =1 + x +y +xy and y ( -1) =0 , then the value of ( y (0) +3 - e^(1//2))

(x^2 - y^2) dx + 2xy dy = 0

Solve: (xy ^ (3) + y) dx + 2 (x ^ (2) y ^ (2) + x + y ^ (4)) dy = 0

The solution of ((dy)/(dx))^(2) + (2x + y) (dy)/(dx) + 2xy = 0 , is

If the solution of differential equation ( dy )/(dx) =1 + x +y^2 + xy ^2 where Y (0) =0 is Y= tan ( x + ( x^2)/( a)) , then a is _______

y^(2) dx + (xy + x^(2) )dy = 0

(y+ x (dy)/(dx)) sin xy =cos x, " when " x= 0 , y =0