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An element having atomic mass 107.9 u ha...

An element having atomic mass 107.9 u has FCC lattice. The edge length of its unit cell is 408.6 pm. Calculate density of the unit cell.
`["Given, "N_(A)=6.022xx10^(23)"mol"^(-1)]`.

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Given data M = 107.9 mol `L^(-1), Z=4, a=408.6 "pm", N_(A)=6.022 times 10^(23)mol^(-1)`
`d=(ZM)/(a^(3)N)`
`=(4 times 107.9 times 10^(-3))/((408.6 times 10^(-12))^(3) times 6.-022 times 10^(23))=10.5 times 10^(3) kgm^(-3)`
`" "=10.5g" "cm^(-3)`
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SUNSTAR PUBLICATION-SUPPLEMENTARY EXAM QUESTION PAPER JULY - 2015-PART - D
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