A nucleus at rest undergoes a decay emitting an `alpha` -particle of de-broglie wavelength `lambda = 5.76 xx 10^(-15) m`. The mass of daughter nucleus is 223.40 amu and that of `alpha`-particle is 4.002 amu - The linear momentum of `alpha` -particle and that of daughter nucleous is -

A nucleus at rest undergoes a decay emitting an a particle of de - Broglie wavelength lambda = 5.76 xx 10^(-15)m if the mass of particle is 4.002amu , determine the total kinetic energy in the final state Hence , obratain the mass of the parent nucleus in amu (1 amu = 931.470 MeV//e^(2))

A nucleus at rest decays by emitting at alpha particle. The de-Broglie wavelenght of emitted alpha particle is lambda=-5.76 femtometer. Mass of the daughter nucleus and alpha particle is 223.610u and 4.002u. Find the mass of the parent nucleus.

In the alpha -decay process occuring in different types of nuclei at rest (i) the K.E. of the daughter nucleus is always greater than the K.E. of the alpha -particle (ii) the K.E. of the daughter nucleus is always less than the K.E. of the alpha -particle (iii) the magnitudes of the linear momenta of the alpha -particle and the daughter nucleus are always equal (iv) the daughter nucleus is always in a stable state

The momentum of a particle which has a de Broglie wavelength of 2.5 xx 10^-10 m is.

A : If a stationary nucleus emits an alpha -perticle , the de Broglie wavelengths of te daugther nucleus and the alpha -perticle and equal . R : The magnitudes of the linear moments of the daughter nucleus and the alpha -perticle are the same .

A nucleus ""^(220)X at rest decays emitting an alpha -particle . If energy of daughter nucleus is 0.2 MeV , Q value of the reaction is

A nucleus ._n^ m X emits one alpha- particle and two beta- particles. The resulting nucleus is

A radio-active elements emits one alpha and beta particles then mass no. of daughter element is :