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Calculate the percentage of nitrogen in ...

Calculate the percentage of nitrogen in urea `NH_2CONH_2`.
Given : R.M.M. of N = 14, C = 12 , O = 16, H = 1 ?

Text Solution

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Relative molecular mass of urea, `NH_2CONH_2`
= (14 x 1 ) + (1 x 2 ) + (12 x 1) + (16 x 1) + (14 x 1) + (1 x 2 )
=14 + 2 + 12 + 16 + 14 + 2
=60
60 g of urea contains 28 gm of N
100 g of urea contains `=(28 xx100)/60` gm of N
=46.66 gm of N
Therefore percentage of nitrogen in urea = 46.66%
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