Home
Class 9
PHYSICS
The separation between two consecutive c...

The separation between two consecutive crests in a transverse wave is 100 m. If wave velocity is 20 m `s^(-1)` , find the frequency of wave.

Text Solution

AI Generated Solution

To solve the problem step by step, we will use the information given in the question and apply the relevant formulas. ### Step 1: Identify the given data - The separation between two consecutive crests (wavelength, λ) = 100 m - Wave velocity (V) = 20 m/s ### Step 2: Write down the formula for frequency The relationship between wave velocity (V), wavelength (λ), and frequency (μ) is given by the formula: ...
Promotional Banner

Topper's Solved these Questions

  • SOUND

    ICSE|Exercise TOPIC 1 Nature of Sound Waves (3 Marks Questions )|12 Videos

  • SOUND

    ICSE|Exercise TOPIC 1 Nature of Sound Waves (4 Marks Questions )|6 Videos

  • REFLECTION OF LIGHT

    ICSE|Exercise EXERCISE 7(C)|54 Videos

  • UPTHRUST IN FLUIDS, ARCHIMEDES' PRINCIPLE AND FLOATATION

    ICSE|Exercise EXERCISE 5(c) (Numerical)|9 Videos

Similar Questions

Explore conceptually related problems

The distance between consecutive crest and trough of a wave is 10 cm . If the speed of wave is 200 cm/s . Then the time period of wave is

Ocean waves of time period 10 s have wave velocity 15 ms^(-1) . Find the wavelength of these waves .

Explain the terms crest and trough in relation to a transverse wave.

The distance between two consecutive crests in a wave train produced in string is 5 m. If two complete waves pass through any point per second, the velocity of wave is :-

The time lag between two particles vibrating in a progressive wave seperated by a distance 20m is 0.02s. The wave velocity if the frequency of the wave is 500Hz, is

Derive an expression of wave velocity in terms of frequency and wavelength of the wave.

A wave is represented by the equation y=0.1 sin (100pit-kx) If wave velocity is 100 m s^(-1) , its wave number is equal to

Stationary waves are produced in 10 m long stretched string. If the string vibrates in 5 segments and wave velocity 20 m/s then the frequency is :-

There are two waves having wavelength 100 cm and 101 cm and same velocity 303 ms^(-1) . The beat frequency is