Fill in the blanks by chossing the appropriate word/words from those given in the brackets: (increases, ionic radius, `CH_(2)`, same, sigma, ionic, 14, 2, decreases, 16, `CH_(3)`, pi, covalent, ionic)
When `N_(2)` goes to `N_(2)^(+)`, the N-N bond distance _____ and when `O_(2)` goes to `O_(2)^(+)` the O-O bond distance _______

Explanation

To solve the question, we need to analyze the changes in bond distances when the molecules \(N_2\) and \(O_2\) are converted to their respective cations \(N_2^+\) and \(O_2^+\).

### Step-by-Step Solution:

1. **Understanding Bond Order**:
- The bond order is a measure of the number of bonds between two atoms. It can be calculated using the formula:
\[
\text{Bond Order} = \frac{(\text{Number of bonding electrons} - \text{Number of antibonding electrons})}{2}
...