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Calculate the pH of a buffer solution containing 0.15 mole of ` CH_3COOH ` and 0.1 mole of `CH_3 COO Na ` per litre. The dissociation constant for acetic acid ` 1.8 xx 10 ^(-5)`

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[Acid] = 0.15 mol `L^(-1)`
[Salt] = 0.1 mol `L^(-1)`
`K_(a)= 1.8 xx 10^(-5)`
pH= pKa + `"log"_(10) (["Salt"])/(["Acid"])`
`= - log 10 (1.8 xx 10^(-5)) + "log"_(10)(0.1)/(0.15)`
`=4.745 + (-0.176)`
=4.569
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