9.00 litres of a gas at 16 atm and 27°C weigh 93.6 g. What is the molecular mass of the gas ?

Explanation

Here, the given data are: P= 16 atm, V= 9.00L, T= `27^(@)C`= 300K, w= 93.6g
According to the gas equation, `PV= (w)/(M) RT OR M= (w RT)/(PV)`
Substituting we get, `M = (93.6 xx 0.0821 xx 300)/(16 xx 9.00)` M= 16.01
Hence the molecular mass of the gas is 16.01.