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On moving a charge of 2C from a point A ...

On moving a charge of 2C from a point A where potential is +12V to a point B where potential is -12 V, the work done is -

A

`+24J`

B

`-24J`

C

48 J

D

`-48J`

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The correct Answer is:
To solve the problem of calculating the work done in moving a charge from point A to point B, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the given values:** - Charge (Q) = 2 C (Coulombs) - Potential at point A (V_A) = +12 V - Potential at point B (V_B) = -12 V 2. **Calculate the change in potential (ΔV):** \[ ΔV = V_B - V_A \] Substituting the values: \[ ΔV = -12 V - (+12 V) = -12 V - 12 V = -24 V \] 3. **Use the formula for work done (W):** The work done in moving a charge in an electric field is given by the formula: \[ W = Q \cdot ΔV \] Substituting the values: \[ W = 2 C \cdot (-24 V) = -48 J \] 4. **Conclusion:** The work done in moving the charge from point A to point B is: \[ W = -48 J \] ### Final Answer: The work done is -48 Joules. ---
To solve the problem of calculating the work done in moving a charge from point A to point B, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the given values:** - Charge (Q) = 2 C (Coulombs) - Potential at point A (V_A) = +12 V - Potential at point B (V_B) = -12 V ...
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