Which of the following statements is correct for BrF?

Options

A. Total number of lone pairs present in 15.
B. Total number of maximum number of atoms in one plane = 5.
C. Molecule is polar.
D. Bromine has its maximum covalency, in this molecule.

Answer

To determine which statement is correct for the molecule BrF (bromine monofluoride), we can analyze the properties and characteristics of this interhalogen compound step by step.

### Step 1: Identify the Nature of BrF
BrF is an interhalogen compound formed by the bonding of two halogens: bromine (Br) and fluorine (F).

**Hint:** Interhalogen compounds are formed by the combination of two different halogens.

### Step 2: Determine Electronegativity
Fluorine is more electronegative than bromine. This means that in the Br-F bond, fluorine will attract the shared electrons more strongly than bromine, resulting in a dipole moment.

**Hint:** Electronegativity differences can create partial charges (δ+ and δ-) in a molecule.

### Step 3: Analyze Valence Electrons
Bromine has 7 valence electrons and fluorine also has 7 valence electrons. When they bond, one valence electron from bromine is used to form a bond with fluorine. Therefore, bromine will have 6 remaining electrons, which will exist as 3 lone pairs.

**Hint:** Count the total valence electrons and how they are used in bonding and lone pairs.

### Step 4: Count the Total Number of Lone Pairs
In BrF, bromine has 3 lone pairs (6 electrons), and fluorine has 3 lone pairs (6 electrons). Therefore, the total number of lone pairs in the molecule is 6 (3 from Br and 3 from F).

**Hint:** Remember to count lone pairs from both atoms in the molecule.

### Step 5: Determine Molecular Polarity
Due to the difference in electronegativity between bromine and fluorine, BrF is a polar molecule. The dipole moment created by the unequal sharing of electrons results in a partial negative charge on fluorine and a partial positive charge on bromine.

**Hint:** A molecule is polar if it has a net dipole moment.

### Step 6: Assess Covalence of Bromine
Bromine can exhibit different covalency levels. In BrF, bromine has a covalency of 1. However, bromine can form other compounds (like BrF3) where it exhibits higher covalency.

**Hint:** Covalency can vary based on the number of bonds formed by an atom in different compounds.

### Conclusion
Based on the analysis:
- The statement regarding the total number of lone pairs being 15 is incorrect (it is 6).
- The statement about the maximum number of atoms in the plane being 5 is incorrect.
- The statement that BrF is polar is correct.
- The statement about bromine having maximum covalence in this molecule is incorrect.

Thus, the correct statement for BrF is that it is a polar molecule.

### Summary of Correct Statement:
BrF is a polar molecule due to the electronegativity difference between bromine and fluorine.