The reaction `2N_(2)O_(5) to NO_(2)+O_(2)` is forming `NO_(2)` at the rate of `0.0072` mole /L/s at some time .
What is the rate of change of `[N_(2)O_(5)]` at this time?

Explanation

To find the rate of change of \([N_2O_5]\) in the reaction \(2N_2O_5 \rightarrow 4NO_2 + O_2\), we can follow these steps:

### Step 1: Write the balanced chemical equation
The balanced equation for the reaction is:
\[ 2N_2O_5 \rightarrow 4NO_2 + O_2 \]

...