At some temperature the rate constant for the decomposition of HI on a gold surface is `0.08 M s^(-1)`
`HI(g) to H_(2)(g)+I_(2)(g)`
What is the order of the reaction ? How long will it take for the concentration of HI to drop from `1.50 M `to `0.30` M ?

Explanation

To solve the problem step by step, we need to determine the order of the reaction and then calculate the time it takes for the concentration of HI to drop from 1.50 M to 0.30 M.

### Step 1: Determine the Order of the Reaction
The rate constant \( k \) is given as \( 0.08 \, \text{M s}^{-1} \). The units of the rate constant can help us determine the order of the reaction.

The general relationship for the units of the rate constant \( k \) for a reaction of order \( n \) is:
\[
k = \text{M}^{1-n} \cdot \text{s}^{-1}
...