Two reactions proceed at `25^(@)C` at the same rate, the temperature coefficient of the rate of the first reaction is 2 and that of the second reactions 2.5. Find the ratio of rates of these reaction at `95^(@)C`

Explanation

At `25^(@)C` the rates of the two reactions are some (say R) . Since the temperature coefficient gives the number of times the rate of a reaction increase by a rise in temperature of `10^(@)` , we have the following results :

Thus , at `95^(@)`
`("rate of second reaction")/(" rate of first reaction") = (2.5^(7)R)/(2^(7)R)= 4.768` .