Bicyclohexane was found to undergo two parallel first order rearrangements . At 730 K , the first order rearrangemen730 K , the first order rate constant for the formation of cyclohexane was measure as `1.26 xx10^(-1)s^(-1)` and for the formation of unethyl cyclopentene the rate constant was `3.8 xx 10^(-5) s^(-1)` . What is the percentage distribution of the rearrangement products ?

Explanation

To solve the problem of determining the percentage distribution of the rearrangement products from bicyclohexane, we will use the rate constants for the two parallel first-order reactions provided.

### Step-by-Step Solution:

1. **Identify the Rate Constants**:
- For the formation of cyclohexane (let's call this product B), the rate constant \( k_1 = 1.26 \times 10^{-1} \, s^{-1} \).
- For the formation of unethyl cyclopentene (let's call this product C), the rate constant \( k_2 = 3.8 \times 10^{-5} \, s^{-1} \).

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