The rate law for the reaction ,
`CH_(3)COC_(2)H_(5)+H_(2)O overset([H^(+)]) toCH_(3)COOH +C_(2)H_(5)OH`
is `(dx)/(dt) =k [CH_(3)COOC_(2)H_(5)][H_(2)O]^(o)`
What will be the effect for the reaction ,
(i) the concentration of `[CH_3COOC_2H_5]` is doubled the effect on the rate is

Explanation

To solve the problem, we need to analyze the effect of doubling the concentration of the reactant \( [CH_3COOC_2H_5] \) (the ester) on the rate of the reaction given by the rate law:

\[ \frac{dx}{dt} = k [CH_3COOC_2H_5][H_2O]^0 \]

### Step-by-Step Solution:

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