The rate of the haemoglobin (Hb)- carbon monoxide reaction ,
`4Hb+3CO to Hb_(4)(CO)_(3)`
has been studied at `20^(@)C` .Concentrations are expressed in `mu ` mole/L .
`{:([Hb](mu"mole/L"),[CO](mu"mole/L"),"Rate of disappearance of Hb"(mu"mole/L/s")),(3.36,1.00,0.941),(6.72,1.00,1.88),(6.72,3.00,5.64):}`
Calculate the rate constant for the reaction

Explanation

To calculate the rate constant for the reaction \( 4 \text{Hb} + 3 \text{CO} \rightarrow \text{Hb}_4(\text{CO})_3 \), we will follow these steps:

### Step 1: Write the rate law expression
The general rate law for the reaction can be expressed as:
\[ R = k [\text{Hb}]^m [\text{CO}]^n \]
where \( R \) is the rate of the reaction, \( k \) is the rate constant, and \( m \) and \( n \) are the orders of the reaction with respect to Hb and CO, respectively.
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