The initial rate of hydrolysis of methyl acetate (1M) by a weak acid `(HA,1M)` is `1//100th` of that of a strong acid `(HX, 1M),` at `25^(@)C`. The `K_(a)(HA)` is

Options

A. `1xx10^(-4)`
B. `1xx10^(-5)`
C. `1xx10^(-6)`
D. `1xx10^(-3)`

Answer

A

Explanation

`R_(HA) =k[H^(+)]_(HA) and R_(HX) =k[H^(+)]_(HX) :. ([H^(+)]_(HX))/([H^(+)]_(HA))=100`
or `[H^(+)]_(HA)=1/100 , "for" Ha: K_(a) = (x^(2))/(1-x)`