If `A={0 , pi/6, pi/4, pi/3, pi/2}` and `f: A rarr B` is a surjection defined by `fx) = cosx` then find `B`

" 07.If "A={0(k)/(6),(pi)/(4)*(pi)/(3),(pi)/(2)}" and "f:A rarr B,f(x)=cos x" is surjection find "B

(pi)/(4)+(2 pi)/(3)-(pi)/(6)

Let f(x)=(1-tan x)/(4x-pi),x!=(pi)/(4),x in[0,(pi)/(2)], If f(x) is continuous in [0,(pi)/(4)], then find the value of f((pi)/(4))

If sinA = 3/5, then B = 1/2, pi/2

Let f(x) = {{:(-2 sin x,"for",-pi le x le - (pi)/(2)),(a sin x + b,"for",-(pi)/(2) lt x lt (pi)/(2)),(cos x,"for",(pi)/(2) le x le pi):} . If f is continuous on [-pi, pi) , then find the values of a and b.

The largest interval lying in (-pi/2,pi/2) for which the function [f(x)=4^-x^2+cos^(-1)(x/2-1)+log(cosx)] is defined, is (1) [0,pi] (2) (-pi/2,pi/2) (3) [-pi/4,pi/2) (4) [0,pi/2)