To what temperature must a gas at 300 K be cooled down in order to reduce its volume to `1//3^(rd)` of its original volume, pressure remaining constant ?

Explanation

To solve the problem of determining the temperature to which a gas at 300 K must be cooled in order to reduce its volume to one-third of its original volume while keeping the pressure constant, we can use Charles's Law. Charles's Law states that the volume of a gas is directly proportional to its temperature when the pressure is held constant. The formula for Charles's Law is:

\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]

### Step-by-Step Solution:

1. **Identify the Given Values:**
- Initial temperature, \( T_1 = 300 \, K \)
...