The length of the simple pendulum is 40 cm. Calculate its time period.
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To calculate the time period of a simple pendulum, we can follow these steps:
### Step-by-Step Solution:
1. **Understand the Formula**:
The time period (T) of a simple pendulum is given by the formula:
\[
T = 2\pi \sqrt{\frac{L}{g}}
...
The length of a simple pendulum is made one-fourth. Its time period becomes :
If the length of a simple pendulum is increased by 2%, then the time period
The length of a simple pendulum is 16 cm . It is suspended by the roof of a lift which is moving upwards with an accleration of 6.2 ms^(-2) . Find the time period of pendulum.
The simple pendulum of length 40 cm is taken inside a deep mine. Assume for the time being that the mine is 1600 km deep. Calculate the time period of the pendulum there. Radius of the earth =6400 km.
If the length of a simple pendulum is equal to the radius of the earth, its time period will be
The length of a simple pendulum is increased four times of its initial valuel, its time period with respect to its previous value will
If the length of a simple pendulum is increased to four times the initial length how is the time period affected?
The time period of oscillation of a simple pendulum is given by T=2pisqrt(l//g) The length of the pendulum is measured as 1=10+-0.1 cm and the time period as T=0.5+-0.02s . Determine percentage error in te value of g.
If the length of a simple pendulum is doubled then the % change in the time period is :
The length of a simple pendulum is decreased by 21% . Find the percentage change in its time period.
ICSE-MEASUREMENTS AND EXPERIMENTATION -TOPIC 2 SIMPLE PENDULUM (4 Marks Questions )
