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A bullet initially moving with a velocit...

A bullet initially moving with a velocity 20 m `s^(-1)` strikes a target and comes to rest after penetrating a distance 10 cm in the target. Calculate the retardation caused by the target.

Text Solution

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Initial velocity = `u= 20 "m s"^(-1)`
Final velocity =v= 0
Distance travelled =s = 10 cm = 0.1 m
Acceleration =a
Using the equation of motion,
`v^2=u^2-2as`
or , `0=20^2+2a xx 0.1`
Or, a=-(400/0.2)
Or, Acceleration =a=-2000 `m s^(-2)`
`therefore` retardation = 2000 `"m s"^(-2)`
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