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A body is thrown vertically upwards with...

A body is thrown vertically upwards with an initial velocity of `9.8 "ms"^(-1)`. What is its speed and direction after 1 s (g=9.8 `"m/s"^2`). Also, find the height to which it will rise.

Text Solution

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u=0,t=(2-1)s=1s
`g=9.8 "ms"^(-2)`
Using the relation :
v=u+gt
v=0-9.8 x 1
`v=9.8 "ms"^(-1)`
For the height to which it will rise
Given , `u=9.8 "ms"^(-1) , g=-9.8 "ms"^(-2)` , t=1s
Using the relation ,
`s=ut+1/2"gt"^2` `=9.8xx1+1/2xx9.8xx(1)^2`
s=14.7 m
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