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A boy on a lift 490 m high drops a stone...

A boy on a lift 490 m high drops a stone. One second later, he throws a second stone after the first. They hit the ground at the same time. With what speed did he thrown the second stone.

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AI Generated Solution

To solve the problem step by step, we will analyze the motion of both stones and apply the relevant physics equations. ### Step 1: Understand the motion of the first stone The first stone is dropped from a height of 490 m. Since it is dropped, its initial velocity (u1) is 0 m/s. We need to find out how long it takes for the first stone to reach the ground. ### Step 2: Use the equation of motion We will use the equation of motion: \[ s = ut + \frac{1}{2}gt^2 \] ...
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