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A convex mirror forms as erect image of ...

A convex mirror forms as erect image of an object of size one third the size of object. If radius of curvature of convex mirror is 36 cm, find the position of object.

Text Solution

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Given, `m=1/3` (positive) for the erect (and virtual)
Image, r=36 cm (positive)
Depending on the point in of the object :
`therefore` From relation , `f=R/2=18` cm (positive )
From relation, `m=-v/u`
`therefore v=-1/3u`
From mirror.s formula, `1/(u)+1/(v)=1/(f)`
`1/(u)+1/(-u/3)=1/18`
`(-2)/u=1/18` or u=-36 cm
Thus the object is at a distance 36 cm in front of the mirror.
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