In an `AC` sub circuit, the resistance `R=0.2Omega`. At a certain instant `(V_(A-V_(B))=0.5` volt, `I=0.5 amp` and `(DeltaI//Deltat)=8A//s`. Find the inductance of the coil:

A coil of resistance 40 Omega is connected across a 4.0 V battery. 0.10 s after the battery is connected, the current in the coil is 63 mA. Find the inductance of the coil.

In a circuit shown in figure the battery emf is equal to E=2.0 V , its internal resistance is r=9.0 Omega , the capacitance of the capacitor is C=10 mu F , the coil inductance is L=100 m H , and the resistance is R=100 Omega . At a certain momenta the switch Sw was disconneted. Find the energy of oscillations in the circuit (b) t=0.30s after the switch was disconnected,

A coil having a resistance of 50.0 Omega and an inductance of 0.5 H is connected to an AC source of 110 , v, 50Hz . The impedance of the coil is (appoximately)

A coil having a resistance of 50.0 Omega and an inductance of 0.500 henry is connected to an AC source of 110 volts , 50.0 cycle//s. Find the rms value of the current in the circuit.

A series circuit consisting of an inductance - free resistance R=0.16 k Omega and coil with active resistance is connected to the mains with effective voltabe V=220 V . Find the heat power generated in the coil if the effective voltage values across the resistance R and the coil are equal to V_(1)=80V and V_(2)=180V respectively.

A capacitor of capacitance 100 muF and a coil of resistance 50 Omega and inductance 0.5 H are connected in series with a 110 V, 50 Hz AC source. Find the rms value of the current.

An average induced emg of 0.20 V appears in a coil when the current in it is changed from 5.0 A in one direction to 5.0 A in the opposite direction in 0.20 s. find the self inductance of the coil.

In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be

In an L-R circuit, an inductance of 0.1 H and a resistance of 1 Omega are connected in series with an ac source of voltage V = 5 sin 10 t. The phase difference between the current and applied voltage will be