The potential energy of a particle moving along x-axis is given by `U = 20 + 5 sin (4 pi x)`, where `U` is in `J` and `x` is in metre under the action of conservative force :

The potential energy of a particle of mass 2 kg moving along the x-axis is given by U(x) = 4x^2 - 2x^3 ( where U is in joules and x is in meters). The kinetic energy of the particle is maximum at

Potential energy of a particle along x-axis varies as U = - 30 + (X-2)^2 , where U is in joule and x is in meter. Hence the particle is in

The potential energt of a particle of mass 0.1 kg, moving along the x-axis, is given by U=5x(x-4)J , where x is in meter. It can be concluded that

The potential energy of a particle oscillating on x-axis is given as U +20 +(x-2)^(2) . The mean position is at

Potential energy of a particle moving along x-axis is by U=(x^(3)/3-4x + 6) . here, U is in joule and x in metre. Find position of stable and unstable equilibrium.

The potential energy of a particle oscillating along x-axis is given as U=20+(x-2)^(2) Here, U is in joules and x in meters. Total mechanical energy of the particle is 36J . (a) State whether the motion of the particle is simple harmonic or not. (b) Find the mean position. (c) Find the maximum kinetic energy of the particle.

The potential energy U(x) of a particle moving along x - axis is given by U(x)=ax-bx^(2) . Find the equilibrium position of particle.

The potential energy of a particle of mass 1kg in motion along the x- axis is given by: U = 4(1 - cos 2x) , where x in metres. The period of small oscillation (in sec) is

The potential energy of body of mass 2 kg moving along the x-axis is given by U = 4x^2 , where x is in metre. Then the time period of body (in second) is

The potential energy of particle of mass 1kg moving along the x-axis is given by U(x) = 16(x^(2) - 2x) J, where x is in meter. Its speed at x=1 m is 2 m//s . Then,