The refracting angle of a prism is `60^(@)` and the refractive index of its material is `sqrt((7)/(3)).` Find the minimum angle of incidence of a ray of light falling on one refracting face of the prism such that the emerging ray will graze the other refracting face.

The refracting angle of a prism is A, and refractive index of the material of the prism is cot (A // 2) . The angle of minimum deviation is

The refracting angle of a prism is 60^(@) and its refractive index is sqrt((7)/(3) . What should be the minimum angle of incidence on the first refracting surface so that the ray can emerge somehow from the second refracting surface?

The relation between angle of the prism and refractive index of the medium is:

If the refracting angle of a prism is A, the refractive index of its material is mu and the angle of deviation of a ray of light incident normally on the first refraction face is delta , then prove that mu = sin(A + delta)/(sinA).

The refractive index of a prism having refracting angle 75^(@) is sqrt2 . What should be the minimum angle of incidence on a refracting surface so that the ray will emerge from the other refracting surface of the prism?

The refractive index of the material of a prism is sqrt(2) and the angle of minimum deviation is 30^(@) . Calculate the value of the refracting angle of the prism.

The refracting angle of a glass prism is 60^(@) and the refractive index of glass is 1.6. If the angle of incidence of a ray of light on the first refracting surface is 45^(@) Calculate the angle of deviation of the ray . Given that sin 26^(@)14' = 0.4419, " " sin33^(@)46' = 0.5558 and sin62^(@)47' = 0.8893

The refractive index of the material of a prism is sqrt((3)/(2)) and the refracting angle is 90^(@) The angle of minimum deviation of the refracted ray by the prism is