What should be the value of the shunt to be connected in parallel to a galcanometer of resistance G, so that 1/n part of the main current will pass through the shunt?

What should be the value of the shunt to be connected in the parallel to a galvanometer to resistance G, so that 1/n part of the main current will pass through the shunt?

If a stunt of 1 Omega is connected to a galvanometer of resistance 99 Omega , what fraction of the main current will flow through the galvanometer?

A shunt of resistance 1 Omega is connected with a galvanometer of resistance 100 Omega . What part of the main current will flow through the galvanometer?

A shunt of resistance 1 Omega is connected with a galvanometer of resistance 100 Omega . What part of the main current will flow through the galvanometer?

If 1 Omega shunt be connected across a galvanometer of 99Omega resistance, what fraction of the main current does the flow through the galvanometer?

When a shunt S is connected across gaivanomenter of resistence G, 1/n of the main current passes through the galvanometer. What is the relation between S and G?

A shunt of resistance r_1 is connected in parallel with a galvanometer of resistance G. A steady source of internal resistance r sends current through the galvanometer.Now, removing the shunt r_1 another resistances r_2 is connected in series with the galvanometer. (i) IF the galvanometer current in either case be the same , show that rG=r_1r_2, (ii) if r=0 and r_1=r_2=G/n , then show that the ratio of galvanometer currents in the two cases is (n+1)/n .

A shunt of 1 Omega is connected in parallel with a galvanometer of resistance 99 Omega . IF the main current of the circuit be 1A, then what will be the galvanometer current?

A battery of internal resistances zero is connected to a galvanometer of resistance 80 Omega and a resistance of 20 Omega in series . A current flows through the galvanometer If a shunt of 1 Omega resistance is connected to the galvanometer, show that the current that will now flow through the galvanometer becomes 1/17 of the previous current.

Two cells such of 0.5Omega and e.m.f. of 1.5V are connected in series to a galvanometer having 8Omega resistance. Calculate the current passing through the circuit.