Define critical angle. A luminous object is placed at a depth h in a medium of refractive index `mu`. Show that the radius r of the circular base of the one through which light can emerge is `r = h // sqrt(mu^(2) - 1)`

What is optical fibre? An object is placed at a depth ‘d’ in a medium of-refractive index mu Show that the radius of the circular base of light cone r = d/sqrt(mu^2-1)

A point source of light is kept at a depth of 'h' in water of r.i 4/3. The radius of the circle at the surface of water through which light emits is

The curved surface area of a right circular cone of height h unit and radius of base r unit is pi rsqrt(h^2+r^2) unit .

A luminous point source is placed at a depth of 30 cm in a source containing a liquid of refractive index 1.25. From the source light rays are being emitted in all directions. The rays which are refracted from the upper surface of the liquid form a circle. Calculate the radius of the circle.

The critical angle of a glass slab in air is 30^(@) . What will be the critical angle if the slab is placed in a medium of refractive index sqrt(2)

A ray of light passing through the medium of refractive index mu_(1) is incident on the surface of separation of another medium of refractive index mu_(2) . A part of the ray is reflected and another part is refracted. What should be the angle of incident so that reflected ray and the refracted ray are at right angles to each other?

A ray of lilght is incident at a small angle theta on a rectangular glass slab of thickness t. IF the refractive index of glass is mu show that the perpendicular distance between the emergent ray from the slab and the incident ray is theta t (mu-1)//mu