The radius of nucleus: `R=R_0A^(1/3)` (`R_0`=constant, A=mass No.). Taking the relation, show that the nuclear density does not depend on mass number A.

R = R_0A^(1//3) ( R_0 = constant, A = Mass Number), R = radius of nucleus. Taking the relation show that of nuclear density does not depend on mass number A .

Write down the relation between radius of nucleus and mass number .

R is a relation over the set of real numbers and it is given by mn ge 0 .Then R is

What will be the gravitational potential on the surface of a planet of mass M and radius R ?

The radius of a uniform sphere is R and its mass is M. The values of the gravitational intensity at distance r_1 and r_2 from the centre of the sphere are F_1 and F_2 respectively. Then,

Let R be the relation on the set R of all real numbers defined by aRb iff |a-b| le 1. Then, R is

Let the relation p be defined on R as apb iff 1+abgt0 . Then

For a nucleus which is nearly spherical in shape r=r_0 A^(1/3) , where r is the radius and A is the mass number and r_0 is a constant of value 1.2xx10^(-15) m. If the mass of the neutrons and protons are equal and equal to 1.67xx10^(-27) kg, prove that density of the nucleus is 2.3xx10^14 times the density of water.

If R _(1) and R _(2) are equivalence rrelations in a set A show that R _(1) nn R _(2) is also an equivalence relation.