Two cells of emf `E_1,E_2` and internal resistances `r_1,r_2` respectively are connected in parallel combination. Determine the equivalent emf of the combination.

Two cells of emf E_1.E_2 and internal resistance r_1 , r_2 respectively are connected to parallel combination. Determine the equivalent emf of the combination.

n electric cells of emf e and internal resistance r each are connected in series.What is the emf of this combination.

R_1 and R_2 are two resistances they are connected in parallel combinations Write down their equivalent resistance in each case.

n electric cells having emf e and internal resistance r each are connected in parallel.What is the emf of this combination?

The series combination of two 10 ohm resistances is connected in parallel combination with a 20 ohm resistance. Determine the equivalent resistance of the final combination.

Two electric cells each of emf 1.5 V and internal resistance 2 Omega are connected in parallel and this combiantion of cells is connected with an external distance of 2 Omega . What will be the current in the external circuit?

Two cells of e.m.f. E_1 and E_2 have internal resistance r_1 and r_2 . Deduce an expression for equivalent e.m.f. of their parallel combination.

Two cells one of emf 1.4 V and internal resistance 0.6 Omega the other of emf 2.5. V and internal resistance 0.3 Omega are connected in parallel and the combination is connected in series with an external resistance of 4 Omega . What is the current through this resistance?

A circuit consists of three batteries of emf E_1 = 1 V, E_2 = 2 V and E_3 = 3 V and internal resistances 1Omega, 2 Omega and 1 Omega respectively which are connected in parallel as shown in the figure. The potential difference between points P and Q is

n identical cells, each of emf e and internal resistance r, are first connected in series and then in parallel. What will be the ratio of the emfs and of the internal resistances of these two cell combinations?