In young's double slit experiment, the fringe width is 2.0 mm.. Determine the separation, between the 9th bright fringe and the 2nd dark fringe.

In Young's double slit experiment the width of the fringe is 2.0 mm. Find the distance between 9th bright band and 2nd dark band.

In Young's double slit experiment, the fringe width is beta . If the entire arrangement is placed in a liquid of refractive index n, the fringe width becomes :

In Young's double slit experiment what is the path difference between the two light waves forming 5th bright band on the screen ?

In Young's double slit experiment the fringe width is found to be 0.4 mm. Now if the whole experiment is conducted by immersing the whole experiment set-up in water ( mu =1.33) the magnitude of fringe width would be

In Young's double slit experiment the fringe width is found to be 0.3 mm. Now if a thin glass plate of refracting index 1.5 is placed in the path of any one of light rays coming from the slits then the width of the fringe will be

How does the fringe width in Young's double slit experiment change when the distance of separation between the slits and screen is double ?

In Young's double slit experiment what is the effect of the following operations on interference fringes ? The separation between the slit is increased.

In Young's double slit experiment the distance of the screen from the plane of the slits is 1.0 m. The wavelength of light used and width of the fringe are 6000 Å and 2 mm respectively. Distance between the slits is

If a Young's double slit experiment were conducted inside water instead of air, the fringe width would

In Young's double slit experiment the distance of the screen from the plane of the slits is 1.0 m. The wavelength of light used and width of the fringe are 6000 Å and 2 mm respectively. If the wavelength of the light used is 4800 Å, the width of the fringe will be