A long straight wire of length of length l is moving within a uniform magnetic field B With a velocity v perpendicular to the field . How much e.m.f. will induced?

A conducting loop in the form of a circle is placed in a uniform magnetic field with its plane perpendicular to the direction of the field. An emf will be induced in the loop if

A straight conductor of length 50 cm is moving with a velocity 5 m. s^(-1) in a magnetic field of strength 2T in a direction perpendicular to the field. What is the emf (in V) induced between the two ends of the conductor?

A conducting wire of length l is rotating with angular velocity w in a magnetic field B perpendicular to it. Prove that the induced e.m.f. at the two ends of the conducting wire is e = 1/2 Bwl^2 .

A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T. The velocity of the conductor is 15 m/s and is directed perpendicular to the field. The emf induced between the two ends of the conductor is

The torque acting on a bar magnet of magnetic moment M in a uniform magnetic field B will be

A moving electron and a moving proton enter a uniform magnetic field in a direction perpendicular to that of the field. If the radii of their circular orbits are equal, they have the same

A metallic loop is placed in a uniform magnetic field B with the plane of the loop perpendicular to B. Under which condition(s) given below an emf will be induced in the loop? "If the loop is…." moved along the direction of vecB squeezed to a smaller area. rotated about its axis. rotated about one of its diameters.

The velocity of a charged particle moving in a magnetic field perpendicular to it is

A charge q moving in a straight line is accelerated by a potential difference V. It enters a uniform magnetic field B perpendicular to its path. Deduce in terms of V an expression for the radius of the circular path in which it travels.