In a potetiometer experiment why is ti necessary to use a long wire?
Length and resistence of a potetiometer wire are 4m and `10Omega` respectively. It is concerned to a cell of mef2 volt. Another cell when joined to this potntiometer and null point is meausred at 250 cm. Find out the emf of the second cell.

In a potentiometer experiment . A cell produces balance in the wire at 240 cm. balancing length change to 120 cm when a resistance 2Omega Is connected parallel to the cell. Find out the internal resistance of the cell.

In a potentiometer experiment , a particular cell produces balance in the wire at 560 cm . If a 10Omega resistance is connected with the cell in parallel ,then this balanced lendth change to 412 cm . Find out the internal resistance of the cell .

The length of the wire of a potentiometer is 100 cm and the emf of a standard cell connected to it is E volt. While measuring the emf of a battery having internal resistance 0.5Omega the null point is obtained at a length of 30 cm . Determine the emf of the battery .

In a potentimeter experiment , it is found that no current passes through the galvanometer when the termials of the cell are connected across 52 cm of the potentimeter wire . If the cell is shunted by a resistance of 5Omega , a balance is found when the cell is connected across 40 cm of the wire . Find the internal resistance of ht cell .

In a potentiometric arrangement ,a cell is connected to the potentiometer wire of 60 cm in length to make the deflection zero in galvanometer . Now if the cell is shunted with a 6Omega resistor , a null point is found in 50 cm length of the wire . What is the internal resistance of the cell ?

A length of potentiometer wire of 155 cm balances the emf of a cell in a circuit and a length of 135 cm when the cell has a conductor of resistance 8Omega connected between its terminals . Find the internal resistance of the cell .

E.M.F. of electrical cell is 2 volt. A 10Omega resistance is joined at its two ends then potential difference in measured 1.6 volt. Find out the internal resistance and lost volt.