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36 cells each of internal reistance 0.5O...

36 cells each of internal reistance `0.5Omega` and `emf1.5V` each are used to sent current an external circuit of `2Omega` reesistance. Find the best mode of grouping them for maximum current of and the current through the external circuit.

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In the circuit shown the current through 2 Omega resistance is

Emf, of a cell is 1.5 V and its internal resistance is 1 Omega When the cell sends current in an external circuit having resistance 2 Omega , then what will be the value of lost volt?

Two cells , one of emf 1.2 V and internal resistance 0.5Omega the other of emf 2 V and internal resiatnce 0.1Omega are connnected in series with an external resistance of 5Omega . What is the current through this resistor ?

A cell of emf 1.5 V and of internal resistance 0.1Omega when connected with a resitor and an ammeter of negligible resistance in series , the ammeter shows a 2.0 A steady current . Find (ii) the power consumed in the resistor .

Emf of an electric cell is 2.1 V and its internal resistance is 0.1 Omega . When the two poles of the cell are connected with an external resistance, a potential difference of 2.08 V is obtained. Determine the value of the external resistance.

Two cells each emf e but of internal resistance r_1 and r_2 are connected in series through and external resistance R. IF the potential difference across the first cell is zero while current flows the value of R in terms of r_1 and r_2 is

5 electric cells are connected in series .Emf of each cell is 1.5 V and internal resistance is 0.1 Omega .When this combination of cells is connected with an external circuit of resistance 4 Omega, what will be the current through that resistance? What resistance should be connected instead of 4 Omega so that the current will be halved?

A cell has an emf of 3V and an internal resistance r. The circuit current is 0.75A when it is connected to an external resistance of 1 Omega . IF the poles are connected directly what will be the current (in A)?

Two cells such of 0.5Omega and e.m.f. of 1.5V are connected in series to a galvanometer having 8Omega resistance. Calculate the current passing through the circuit.

UNITED BOOK HOUSE-QUESTION PAPER 2019-EXAMPLE
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