Group of N cells whose e.m.f. varies directly with the internal resistance, as per the equation `E_N = 1.5 r_N` are connected as shown in fig .Find the current I in the circuit.

Two cells, whose e.m.f.'s are same are connected in series. Their internal resistance are r_1 and r_2 respectively and r_1gtr_2 . When this combination is connected with an external resistance R then potential difference between the terminals of first cell becomes zero. The value of resistance R will be

n number of cells e.m.f of each is E and internal resistance is r connected in parallel or series combination and are connect to external resistance R.Same current flows through R in both cases. Then—

Four cells each of emf E are internal resistance r, are connected In series across an external resistance R. By mistake one of the cells is connected in reverse. Then the current in the external circuit is

Four cells, each of emf E and internal resistance r , are connected in series across an external resistance R By mistake one of the cells is connected in reverse. Then the current in the external circuit is

A cell of emf e and internal resistance r is connected to a variable resistance R as shown in Fig.Match the statements given-Jn Column-I with the conditions stated in Column-ll,

Two cells each emf e but of internal resistance r_1 and r_2 are connected in series through and external resistance R. IF the potential difference across the first cell is zero while current flows the value of R in terms of r_1 and r_2 is

Two cells each of emf e but internal resistances r_1 and r_2 are connected in series through an external resistance R. IF the potential difference across the first cell is zero while current flows,the relation of R in terms of r_1 and r_2 is

Two cells each of emf e but internal resistance r_1 and r_2 are connected in series through an external resistance R. IF the potential difference across the first cell is szero while current flow, the relation of R in terms of r_1 and r_2